5y^2+4y+1=0

Solution for 5y^2+4y+1=0 equation:

Simplifying
5y2 + 4y + 1 = 0

Reorder the terms:
1 + 4y + 5y2 = 0

Solving
1 + 4y + 5y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.2 + 0.8y + y2 = 0

Move the constant term to the right:

Add '-0.2' to each side of the equation.
0.2 + 0.8y + -0.2 + y2 = 0 + -0.2

Reorder the terms:
0.2 + -0.2 + 0.8y + y2 = 0 + -0.2

Combine like terms: 0.2 + -0.2 = 0.0
0.0 + 0.8y + y2 = 0 + -0.2
0.8y + y2 = 0 + -0.2

Combine like terms: 0 + -0.2 = -0.2
0.8y + y2 = -0.2

The y term is 0.8y.  Take half its coefficient (0.4).
Square it (0.16) and add it to both sides.

Add '0.16' to each side of the equation.
0.8y + 0.16 + y2 = -0.2 + 0.16

Reorder the terms:
0.16 + 0.8y + y2 = -0.2 + 0.16

Combine like terms: -0.2 + 0.16 = -0.04
0.16 + 0.8y + y2 = -0.04

Factor a perfect square on the left side:
(y + 0.4)(y + 0.4) = -0.04

Can't calculate square root of the right side.

The solution to this equation could not be determined.